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use super::*;
#[test]
fn same_range_first_consumers_return_correct_answer() {
let find_op = |x: &i32| x % 2 == 0;
let first_found = AtomicUsize::new(usize::max_value());
let far_right_consumer = FindConsumer::new(&find_op, MatchPosition::Leftmost, &first_found);
// We save a consumer that will be far to the right of the main consumer (and therefore not
// sharing an index range with that consumer) for fullness testing
let consumer = far_right_consumer.split_off_left();
// split until we have an indivisible range
let bits_in_usize = usize::min_value().count_zeros();
for _ in 0..bits_in_usize {
consumer.split_off_left();
}
let reducer = consumer.to_reducer();
// the left and right folders should now have the same range, having
// exhausted the resolution of usize
let left_folder = consumer.split_off_left().into_folder();
let right_folder = consumer.into_folder();
let left_folder = left_folder.consume(0).consume(1);
assert_eq!(left_folder.boundary, right_folder.boundary);
// expect not full even though a better match has been found because the
// ranges are the same
assert!(!right_folder.full());
assert!(far_right_consumer.full());
let right_folder = right_folder.consume(2).consume(3);
assert_eq!(
reducer.reduce(left_folder.complete(), right_folder.complete()),
Some(0)
);
}
#[test]
fn same_range_last_consumers_return_correct_answer() {
let find_op = |x: &i32| x % 2 == 0;
let last_found = AtomicUsize::new(0);
let consumer = FindConsumer::new(&find_op, MatchPosition::Rightmost, &last_found);
// We save a consumer that will be far to the left of the main consumer (and therefore not
// sharing an index range with that consumer) for fullness testing
let far_left_consumer = consumer.split_off_left();
// split until we have an indivisible range
let bits_in_usize = usize::min_value().count_zeros();
for _ in 0..bits_in_usize {
consumer.split_off_left();
}
let reducer = consumer.to_reducer();
// due to the exact calculation in split_off_left, the very last consumer has a
// range of width 2, so we use the second-to-last consumer instead to get
// the same boundary on both folders
let consumer = consumer.split_off_left();
let left_folder = consumer.split_off_left().into_folder();
let right_folder = consumer.into_folder();
let right_folder = right_folder.consume(2).consume(3);
assert_eq!(left_folder.boundary, right_folder.boundary);
// expect not full even though a better match has been found because the
// ranges are the same
assert!(!left_folder.full());
assert!(far_left_consumer.full());
let left_folder = left_folder.consume(0).consume(1);
assert_eq!(
reducer.reduce(left_folder.complete(), right_folder.complete()),
Some(2)
);
}
// These tests requires that a folder be assigned to an iterator with more than
// one element. We can't necessarily determine when that will happen for a given
// input to find_first/find_last, so we test the folder directly here instead.
#[test]
fn find_first_folder_does_not_clobber_first_found() {
let best_found = AtomicUsize::new(usize::max_value());
let f = FindFolder {
find_op: &(|&_: &i32| -> bool { true }),
boundary: 0,
match_position: MatchPosition::Leftmost,
best_found: &best_found,
item: None,
};
let f = f.consume(0_i32).consume(1_i32).consume(2_i32);
assert!(f.full());
assert_eq!(f.complete(), Some(0_i32));
}
#[test]
fn find_last_folder_yields_last_match() {
let best_found = AtomicUsize::new(0);
let f = FindFolder {
find_op: &(|&_: &i32| -> bool { true }),
boundary: 0,
match_position: MatchPosition::Rightmost,
best_found: &best_found,
item: None,
};
let f = f.consume(0_i32).consume(1_i32).consume(2_i32);
assert_eq!(f.complete(), Some(2_i32));
}