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/*
* Copyright © 2010 Valve Software
*
* Permission is hereby granted, free of charge, to any person obtaining a
* copy of this software and associated documentation files (the "Software"),
* to deal in the Software without restriction, including without limitation
* the rights to use, copy, modify, merge, publish, distribute, sublicense,
* and/or sell copies of the Software, and to permit persons to whom the
* Software is furnished to do so, subject to the following conditions:
*
* The above copyright notice and this permission notice (including the next
* paragraph) shall be included in all copies or substantial portions of the
* Software.
*
* THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY KIND, EXPRESS OR
* IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES OF MERCHANTABILITY,
* FITNESS FOR A PARTICULAR PURPOSE AND NONINFRINGEMENT. IN NO EVENT SHALL
* THE AUTHORS OR COPYRIGHT HOLDERS BE LIABLE FOR ANY CLAIM, DAMAGES OR OTHER
* LIABILITY, WHETHER IN AN ACTION OF CONTRACT, TORT OR OTHERWISE, ARISING
* FROM, OUT OF OR IN CONNECTION WITH THE SOFTWARE OR THE USE OR OTHER DEALINGS
* IN THE SOFTWARE.
*/
#include <stdint.h>
/*
* Code for fast 32-bit unsigned remainder, based off of "Faster Remainder by
* Direct Computation: Applications to Compilers and Software Libraries,"
*
* util_fast_urem32(n, d, REMAINDER_MAGIC(d)) returns the same thing as
* n % d for any unsigned n and d, however it compiles down to only a few
* multiplications, so it should be faster than plain uint32_t modulo if the
* same divisor is used many times.
*/
#define REMAINDER_MAGIC(divisor) \
((uint64_t) ~0ull / (divisor) + 1)
/*
* Get bits 64-96 of a 32x64-bit multiply. If __int128_t is available, we use
* it, which usually compiles down to one instruction on 64-bit architectures.
* Otherwise on 32-bit architectures we usually get four instructions (one
* 32x32->64 multiply, one 32x32->32 multiply, and one 64-bit add).
*/
static inline uint32_t
_mul32by64_hi(uint32_t a, uint64_t b)
{
#ifdef HAVE_UINT128
return ((__uint128_t) b * a) >> 64;
#else
/*
* Let b = b0 + 2^32 * b1. Then a * b = a * b0 + 2^32 * a * b1. We would
* have to do a 96-bit addition to get the full result, except that only
* one term has non-zero lower 32 bits, which means that to get the high 32
* bits, we only have to add the high 64 bits of each term. Unfortunately,
* we have to do the 64-bit addition in case the low 32 bits overflow.
*/
uint32_t b0 = (uint32_t) b;
uint32_t b1 = b >> 32;
return ((((uint64_t) a * b0) >> 32) + (uint64_t) a * b1) >> 32;
#endif
}
static inline uint32_t
util_fast_urem32(uint32_t n, uint32_t d, uint64_t magic)
{
uint64_t lowbits = magic * n;
uint32_t result = _mul32by64_hi(d, lowbits);
assert(result == n % d);
return result;
}