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// `str.charCodeAt(0)` doesn't need to inspect the right rope child, because
// the first character is guaranteed to be in the left child.
const ropes = [
newRope("ABCDEFGHIJKL", "MNOPQRSTUVWXYZ"),
newRope("abcdefghijkl", "mnopqrstuvwxyz"),
newRope("A", "BCDEFGHIJKLMNOPQRSTUVWXYZ"),
newRope("a", "bcdefghijklmnopqrstuvwxyz"),
];
for (let i = 0; i < 500; ++i) {
let rope = ropes[i & 3];
let actual = rope.charCodeAt(0);
let expected = 0x41 + (i & 1) * 0x20;
assertEq(actual, expected);
}